MATP6600/DSES6780 Nonlinear Programming, Homework 6.
Due: Friday, December 2, 2011, by the end of class.
Each question is worth 20 points.

has a saddle point at the origin and two global minima at ±(1,-1). We investigate solving this problem using Newton’s method.
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![1 [ 2 - 1 ]
G = -- .
8 - 1 2](hw62x.png)
Assume the algorithm starts from a nonzero point with an indefinite Hessian. Show that the algorithm eventually obtains a point with a positive definite Hessian. What can you then conclude from question 1?

This problem has optimal solution x = (0,-20). One penalty function approach to this problem is to use a penalty parameter μ and solve

Use AMPL and a solver on the NEOS server (or another package) to solve this problem for various values of μ. Show empirically that increasing μ by a factor of ten results in a solution to (NLP) with about one more digit of accuracy.
| John Mitchell |
| Amos Eaton 325 |
| x6915. |
| mitchj at rpi dot edu |
| Office hours: Tuesday 12.0 – 2.0, Wednesday 2.0 – 4.0. |